Question

Which ordered pair makes both inequalities true?

y > –3x + 3

y > 2x – 2


(1,0)
(–1,1)
(2,2)
(0,3)

Answer 1

None of those pairs can make this inequality true...

Answer 2

All options are wrong.

Explanation:

We have y > –3x + 3 and y > 2x – 2

Option A - (1,0)

y > –3 x 1 + 3 = 0

We have y = 0, which is not greater than 0.

Option A is not correct.

Option B - (–1,1)

y > –3 x -1 + 3 = 6

We have y = 1, which is not greater than 6.

Option B is not correct.

Option C - (2,2)

y > –3 x 2 + 3 = -3

We have y = 2, which is greater than -3.

y > 2 x 2 – 2 = 2

We have y = 2, which is not greater than 2.

Option C is not correct.

Option D - (0,3)

y > –3 x 0 + 3 = 3

We have y = 3, which is not greater than 3.

Option D is not correct.

All options are wrong.