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Evaluate -a^n when a=3 and n=2,3,4, and 5. Now evaluate (-a)^n when a=3 and n=2,3,4, and 5. Based on the sample, does it appear that -a^n = (-a)^n? If not, state the relationships,if any, between the two.

User CaseyWebb
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The attachment shows the requested evaluations.

-a^n ≠ (-a)^n . . . . except when n is an odd integer

Evaluate -a^n when a=3 and n=2,3,4, and 5. Now evaluate (-a)^n when a=3 and n=2,3,4, and-example-1
User Mansukh Ahir
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