Question

What value of x
in the solution set of 2(3x – 1) ≥ 4x – 6?

Answer 1

First, you must distribute 2(3x-1).
To do that, you will multiply 2•3x, and 2•-1 because you are taking the number outside of the parentheses and multiplying (distributing) it to all the numbers inside

After distributing, the left side of your inequality will be 6x-2

Now you have

`6x - 2 \geqslant 4x - 6`

To find the value of x, you must subtract an x value from both sides of the equation, as well as a constant from each side.

so you have

`6x - 2 \geqslant 4x - 6 \\ - 6x \geqslant + 6`
And that will make the equation

`- 4 \geqslant - 2x`
Now, divide the variable side, ***BUT, because you are dividing by a negative number in an inequality, the inequality will switch sides.

Then, the value of x is greater than or equal to 2

Answer 2

-1

Explanation: