Answer:
It's both an A. P and a G. P series.
Explanation:
Let's prove using A.P with a common difference (d) = 13
Let's say we want to find the second number
a + (n - 1)d
a = 13, n = 4, d = 13
.: S2= 13 + ( 2- 1)13
S2= 13 + (1) 13
S2= 13 + 13 = 26
Let's show using a G. P series.
S2 = arⁿ—¹
S2 = 13 × 2²—¹
S2 = 13 × 2¹
S2 = 13 × 2 = 26