Which function has a domain of all real numbers except x=pi/2+_npi? A. Y=cos x B. Y=cot x C. Y= 1/sinx D. Y=sec x

QAmmunity.org

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question

asked Feb 26, 2019 69.7k views

0 votes

Which function has a domain of all real numbers except x=pi/2+_npi?

A. Y=cos x
B. Y=cot x
C. Y= 1/sinx
D. Y=sec x

Mathematics
middle-school

Madno asked

by Madno

7.7k points

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

3 votes

The answer would be D. Y=secx

Hope this helps and good luck!

Tamanakid answered Mar 5, 2019

by Tamanakid

7.7k points

0 Comments

Please log in or register to add a comment.

← Prev Question Next Question →

Related questions

asked Aug 11, 2017 231k views

1.What basic trigonometric identity would you use to verify that cot x sin x = cos x? . . a. cos^2x+sin^2x=1. b. cot x= cosx/sinx. c. cos x= 1/sec x. d. sin x= 1/csc x. . 2.What basic trigonometric identity

Ryan Tice asked Aug 11, 2017

by Ryan Tice

7.8k points

Mathematics
high-school

2 answers

4 votes

231k views

asked Nov 4, 2017 114k views

Which of the following equations are identities? cot x = cosx/sinx tanx = 1/cot x cscx = 1/cos x cscx = 1/sec x

Txs asked Nov 4, 2017

by Txs

8.2k points

Mathematics
high-school

2 answers

0 votes

114k views

asked Apr 12, 2021 94.2k views

I need help proving a few trigonometric identities. tanA = tanA * cscA^(2) + cot(-A) csc^(2) \beta -csc^(2) \beta *sec^(2) \beta = -sec^(2) \beta cscx+cotx=(sinx)/(1-cosx) (secx+tanx)^(2) = (cscx+1)/(cscx

Reznoir asked Apr 12, 2021

by Reznoir

8.5k points

Mathematics
high-school

1 answer

4 votes

94.2k views

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Related questions

Other Questions