Question

An eagle carry a trout flies above a lake along a horizontal path. The eagle drops the trout from a height of 6.1m. The fish travels7.9 m horizontally before hitting the water. What is the velocity of the eagle?

Answer 1

7.1

Step-by-step explanation:

did endgenuity, said it's correct

(explanation above is correct, also)

Answer 2

Velocity of the eagle = 7.08 m/s

Step-by-step explanation:

We have equation of motion ,
`s= ut+(1)/(2) at^2`, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Vertical motion of fish:

Initial velocity = 0 m/s , acceleration = acceleration due to gravity =
`9.8m/s^2`, displacement = 6.1 m we need to find time.

`6.1= 0*t+(1)/(2) *9.8*t^2\\ \\ 4.9t^2=6.1\\ \\ t=1.116 seconds`

Horizontal motion of fish:

Acceleration = acceleration due to gravity =
`0m/s^2`, displacement = 7.9 m , time = 1.116 seconds we need to find Initial velocity (u).

`7.9= u*1.116+(1)/(2) *0*1.116^2\\ \\ u=7.08m/s`

So, velocity of the eagle = 7.08 m/s