Question

A. A student was given an unknown sample of a pure metal to identify. Its mass was 116

g. He determined that 511 J of energy raised the temperature of the sample from 21.6°C
to 40.5°C. Based on his measurements, what kind of metal was the sample? (4 points)

Answer 1

READ THE EXPLAINATION

Step-by-step explanation:

It says show your work.

40.5°C – 21.6°C = 18.9°C

So, the metal was raised 18.9 deg Celsius.

It took 511 J of energy to raise the metal 18.9 deg Celsius.

511/ 18.9 = 27.03

It takes 27.03 J to raise 116 g of the metal 1 degree.

27.03/116 = .233

It takes .233 J to raise 1 gram of the metal 1 degree.

Therefore, the specific heat capacity of the metal is .233 J

According to the Specific heat values table, Silver has a specific heat capacity of .233.

The metal is silver.

Answer 2

Silver

Step-by-step explanation:

Given parameters:

Mass = 116g

Energy = 511J

Initial temperature = 21.6°C

Final temperature = 40.5°C

Unknown:

Specific heat capacity and the type of metal = ?

Solution:

To solve this problem, we need to find the specific heat capacity of the metal given,

H = m x c x Ф

H is the energy

m is the mass

c is the specific heat capacity

Ф is the change in temperature

511 = 116 x c x (40.5 - 21.6)

511 = 2192.4c

c = 0.233J/g°C

The specific heat capacity of silver is similar to this.