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The size of a TV is measured by its diagonal. You want to buy a TV that has a 32-inch screen and a height of 15.7 inches. What is the width of the TV?

User Cyberz
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the answer to this question is 27.88

User Igor Bubelov
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Think of the space created with the diagonal line like a triangle. There are three sides. the longest side, the diagonal line is 32 inches. one of the other sides is 15.7 inches. Using Pythagoras theorem, we know that a^2 + b^2 = c^2, where c is the longest side of the triangle (32inches) and either a or b is 15.7inches. let's say that a is 15.7 inches. if we substitute these values we just assigned to a and c into Pythagoras' theorem above, we get 15.7^2 +b^2 = 32^2. we can simplify this to 246.49 + b^2 = 1024. We then subtract 246.49 from both sides of the equation to get b^2 = 777.51. we then square root both sides of the equation to get b = 27.88 (rounded to 2 decimal places). because b is the width of the TV, the width of the TV is 27.88 inches.

{a}^(2) + {b}^(2) = {c}^(2) \\ {15.7}^(2) + {b}^(2) = {32}^(2) \\ 246.49 + {b}^(2) = 1024 \\ {b}^(2) = 777.51 \\ b = √(777.51) \\ b = 27.88
User Stoiczek
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