Question

How much heat is absorbed by a 72g iron skillet when its temperature rises from 14oc to 24oc?

Answer 1

The answer to this question is 331.59 J

Step-by-step explanation

As we know Specifi Heat formula that

`Q=mCpΔT`

The mass is = 72 g (72/1000 = 0.072 kg)

`ΔT = 24-14 = 10^(o)C`

`Cp for iron = 460.548 J/(kg^(o)C)`

Put the values in formula

`Q = 0.072 * 10 * 460.548`

`Q = 331.59 J`

So, absorbed heat will be 331.59 J