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Write the equation of a line that is PERPENDICULAR to the line y=3x-4 and passes through the point (-6,1)​
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Write the equation of a line that is PERPENDICULAR to the line y=3x-4 and passes through the point (-6,1)​

User Sasynkamil
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1 Answer

4 votes

Answer: y = -1/3x - 1

Explanation:

  • Slope of perpendicular line is opposite reciprocal --> -1/3
  • Using point given (-6, 1), find b.
  • 1 = -6(-1/3) + b
  • 1 = 2 + b
  • -1 = b

User Lschuetze
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