Question

If 0.035pC of charge is transferred via the movement of Al3+ ions, how's many of these must be transferred in total? Please add an explanation with your answer as I'm completely stuck.

Answer 1

Each
`Al^+^3` ion contains three extra protons. Hence, the extra charge on each
`Al^+^3` =
`3 * 1.6 * 10^-^1^9` C

Total charge = 0.035 pC

Total charge (Q) =
`0.035 * 10^-^1^2` C

Let the number of
`Al^+^3` ions be n.

According to question:

`n * 3 * 1.6 * 10^-^1^9 =0.035 * 10^-^1^2`

`n = (0.035 * 10^-^1^2)/(3 * 1.6 * 10^-^1^9)`

`n = 7.29167 * 10^4`

n = 72917

Hence, the total number of ions needed to be transferred is 72917