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Solve for the perimeter and area of a rectangle that has a length of 4in. and a width of 2 in
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Solve for the perimeter and area of a rectangle that has a length of 4in. and a width of 2 in

User Zionyx
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2 Answers

5 votes
The perimeter is either 10 (if the rectangle has two sides that are 4in and one side that is 2in) or 8 (if the rectangle has two sides that are 2in and one side that is 4in)
User Talles
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5.8k points
6 votes
p=4+4+2+2
=8+4
=12in

A=l×w
=4×2
=8in^2
User Udenyi
by
5.8k points
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