162k views
4 votes
Jim has a total of 77 red and blue marbles. The number of blue marbles is five more than twice the number of red marbles.

2 Answers

3 votes

Answer:

Explanation:

r + 2r+5 = 77

3r = 72

red = 24 (# of red marbles)

----------------

Solve for "b"::

b = 77 - r = 77-24 = 53 (# of blue marbles)

--------------

Cheers,

Stan H.

User TechyGypo
by
7.8k points
5 votes

Let r and b represent, respectively, the number of red and blue marbles. We know a couple of things:

  • The total number of marbles is 77, so
    r+b = 77
  • The number of blue marbles is five more than twice the number of red marbles, so
    b = 2r+5

So, we have the following system:


\begin{cases} r+b = 77\\b = 2r+5\end{cases}

The second equation gives a way to express b in terms of r. Use this expression in the first equation:


r+b = 77 \iff r+(2r+5)=77 \iff 3r+5=77 \iff 3r = 72 \iff r = 24

So, if Jim has 24 red marbles, he has
77-24 = 53 blue marbles.


User Hargo
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories