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Jim has a total of 77 red and blue marbles. The number of blue marbles is five more than twice the number of red marbles.

2 Answers

3 votes

Answer:

Explanation:

r + 2r+5 = 77

3r = 72

red = 24 (# of red marbles)

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Solve for "b"::

b = 77 - r = 77-24 = 53 (# of blue marbles)

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Cheers,

Stan H.

User TechyGypo
by
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5 votes

Let r and b represent, respectively, the number of red and blue marbles. We know a couple of things:

  • The total number of marbles is 77, so
    r+b = 77
  • The number of blue marbles is five more than twice the number of red marbles, so
    b = 2r+5

So, we have the following system:


\begin{cases} r+b = 77\\b = 2r+5\end{cases}

The second equation gives a way to express b in terms of r. Use this expression in the first equation:


r+b = 77 \iff r+(2r+5)=77 \iff 3r+5=77 \iff 3r = 72 \iff r = 24

So, if Jim has 24 red marbles, he has
77-24 = 53 blue marbles.


User Hargo
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5.5k points