Question

a student moved up north along vector v1 and north east along vector v2 as shown in the diagram. if the magnitude of v1 is 7, x=4, and y=3 determine the magnutude of v2, the magnitude of r and the direction of R

Answer 1

`v_1 = 7`

x = 4

y = 3

From the diagram, it is clear that the x and y are the component of the
`v_2` vector. Since, x and y are perpendicular.

Hence,

`v_2 = √(x^2 + y^2)`

`v_2 = √(4^2 + 3^2)`

`v_2 =√(16 + 9)`

`v_2 = √(25)\\`

`v_2 = 5`

Now,
`v_1` and x are in the same direction. Hence, we can add the magnitude.

`= v_1 + x`

= 7 + 4

`v_1 + x= 11`

y and
`(v_1 + x)` are perpendicular and they are the components of R

Hence, the magnitude of R:

`R = √((v_1 +x)^2 + y^2)`

`R = √(11^2 + 3^2) =√(121 +9) = √(130)`

R = 11.4