229k views
2 votes
Write the equation of a line that is parallel to y=0.75x and passes through the point (8,0)

2 Answers

3 votes
A line passing parallel to y = 0.75x will be of the form:


y = 0.75x + k

where k is a constant.

It passes through (8,0)

Thus,


y = 0.75x + k \\ \\ 0 = 0.75 * 8 + k \\ \\ 0 = 6 + k \\ \\k = - 6


\textbf{The equation is \: \: y = 0.75x - 6}
User Damote
by
8.0k points
7 votes
Standard form of linear eqn : y=mx+c
m= gradient
c= y intercept

Line that is parallel = Same Gradient
Eqn of 2nd Line : y=0.75x+c
Given (8,0) where x=8 and y =0,
0=(0.75)(8) + c
c = -6
Therefore y=0.75x-6
User WaterFox
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories