Question

Write the equation of a line that is parallel to y=0.75x and passes through the point (8,0)

Answer 1

A line passing parallel to y = 0.75x will be of the form:


`y = 0.75x + k`

where k is a constant.

It passes through (8,0)

Thus,


`y = 0.75x + k \\ \\ 0 = 0.75 * 8 + k \\ \\ 0 = 6 + k \\ \\k = - 6`


`\textbf{The equation is \: \: y = 0.75x - 6}`

Answer 2

Standard form of linear eqn : y=mx+c
m= gradient
c= y intercept

Line that is parallel = Same Gradient
Eqn of 2nd Line : y=0.75x+c
Given (8,0) where x=8 and y =0,
0=(0.75)(8) + c
c = -6
Therefore y=0.75x-6