Question

How many grams of F are in 145 g of CaF2?

Answer 1

Ca = 48.1, F = 19.0 -> 2F = 38.0
--> CaF2 = 78.1
%F/CaF2 = 38.0/78.1 = 48.7%
-->

`0.487 * 145 = 70.615`

Answer 2

The amount of F present in 145 g CaF2 is 35.3 g (≅35 g)

Step-by-step explanation:

Given:

Mass of CaF2 = 145 g

To determine:

Mass of F present in 145 g of CaF2

Step-by-step explanation:

Based on the formula stoichiometry for CaF2:

1 mole of Caf2 contains 2 moles of F

Molar mass of CaF2 = Atomic weight of Ca + 2(atomic weight of F)

= 40 + 2(19) = 78 g

Atomic mass of F = 19 g

i.e. 78 g of CaF2 contains 19 g of F

Amount of F present in the given 145 g of CaF2 would be:

`=(145 g\ CaF2 * 19g\ F)/(78 g \ CaF2 ) =35.3 g\ F`