Question

Solve for xxx. -4x+60<72 \quad \maroonc{\text{ or }} \quad 14x+11<-31−4x+60<72 or 14x+11<−31minus, 4, x, plus, 60, is less than, 72, space, start color maroonc, space, o, r, space, end color maroonc, space, 14, x, plus, 11, is less than, minus, 31 choose 1 answer: choose 1 answer:

Answer 1

The solution to the system of inequalities is the empty set.

The given compound inequality consists of two separate inequalities:

-4x+60<72

14x+11<-31

To solve the first inequality, we can subtract 60 from both sides and then divide both sides by -4:

-4x+60<72

-4x<72-60

-4x<12

x>-3

To solve the second inequality, we can subtract 11 from both sides and then divide both sides by 14:

14x+11<-31

14x<-31-11

14x<-42

x<-3

Therefore, the solution to the first inequality is x>-3, and the solution to the second inequality is x<-3.

However, since the question asks for the solution to both inequalities, we only want the values of x that satisfy both conditions. This means we need to find the overlap between the two sets of solutions.

Since x cannot be both greater than -3 and less than -3, the solution to both inequalities is the empty set. In other words, there is no value of x that satisfies both -4x+60<72 and 14x+11<-31.

Question:-

Solve for x. -4x+60<72 OR 14x+11