Question

Kieran, Jermaine and Chris play football.

Kieran has scored 8 more goals than Chris.
Jermaine has scored 5 more goals than Kieran.
Altogether they have scored 72 goals.
How many goals did they each score?

Answer 1

By setting up a system of linear equations based on the information given, we find out that Chris scored 17 goals, Kieran scored 25 goals, and Jermaine scored 30 goals.

Step-by-step explanation:

The question involves solving a system of linear equations to determine the number of goals scored by each player in a football game. Let's denote the number of goals scored by Chris as C. According to the information given, Kieran scored 8 more goals than Chris, which means Kieran scored C+8 goals. Jermaine scored 5 more goals than Kieran, which means Jermaine scored (C+8)+5 = C+13 goals. Together, they scored a total of 72 goals, which gives us the equation C + (C+8) + (C+13) = 72.

Let's solve this equation:

• C + C + 8 + C + 13 = 72
• 3C + 21 = 72
• 3C = 72 - 21
• 3C = 51
• C = 17

Now that we have the number of goals Chris scored, we can find out Kieran's and Jermaine's scores.

• Kieran's goals: C+8 = 17+8 = 25
• Jermaine's goals: C+13 = 17+13 = 30

In summary, Chris scored 17 goals, Kieran scored 25 goals, and Jermaine scored 30 goals.

Answer 2

Step-by-step explanation:

Find an equation that explains the problem. We can see how many goals the players have scored in comparison to each other. The person with the fewest goals is Chris. Let us say he score x goals. Then we can see that Kieran has scored 8 more than Chris, i.e. x + 8. Jermaine scored 5 more goals than Kieran, therefore x + 8 + 5 = x + 13. Now we have the amount of goals each person scored relative to each other. The total number of goals scored was 72, thus all of these amounts must equal 72.

x + (x + 8) + (x + 13) = 72

Now we can rearrange and solve for x.

3x + 21 = 72

3x = 51

x = 17