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Given that f(x) = 6x2 + 72, find x.

User Niculare
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2 Answers

3 votes

We have been given that


f(x) = 6x^(2) +72


f(x)-72=6x^(2)


(f(x)-72)/(6) =x^(2)


x=\sqrt{(f(x)-72)/(6) }

Hence,
x=\sqrt{(f(x)-72)/(6) }.

User Nova Entropy
by
8.0k points
4 votes

Answer:

Values of x are:

±2i√3

Explanation:

We have to find x in f(x)=6x²+72

i.e. those values of x for which

6x²+72=0

Subtracting 72 from both sides, we get

6x² = -72

Dividing both sides by 6, we get

x² = -12

Taking square root on both sides, we get

x = ±2i√3

Hence, Values of x are:

±2i√3

User Mike Mayo
by
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