Question

Given that f(x) = 6x2 + 72, find x.

Answer 1

We have been given that

`f(x) = 6x^(2) +72`

`f(x)-72=6x^(2)`

`(f(x)-72)/(6) =x^(2)`

`x=\sqrt{(f(x)-72)/(6) }`

Hence,
`x=\sqrt{(f(x)-72)/(6) }`.

Answer 2

Values of x are:

±2i√3

Explanation:

We have to find x in f(x)=6x²+72

i.e. those values of x for which

6x²+72=0

Subtracting 72 from both sides, we get

6x² = -72

Dividing both sides by 6, we get

x² = -12

Taking square root on both sides, we get

x = ±2i√3

Hence, Values of x are:

±2i√3