Question

Write the equation of the line
Through the given point. Use slope intercept form.

Answer 1

The slope of the given line = (-1/(-6/5)) = 5/6 It passes through; (-9,1) Using the slope intercept form; y - y1 =m(x-x2) y-1=5/6(x--9) » y -1 = 5/6(x+9) Multiplying through by 6 gives 5y-5 = 5(x+9) Expanding brackets we have; 6y-6 = 5x+45 6y-5x-51= 0 is the required equation.

Answer 2

The equation for this line would be y = 5/6x + 17/2

In order to find this, we first need to start with the slope. Perpendicular lines have opposite and reciprocal slopes. Therefore, to be perpendicular to a line with a -6/5 slope, our new line would need to have a 5/6 slope.

Next we use that along with the given point in slope intercept form to find the intercept.

y = mx + b

1 = 5/6(-9) + b

1 = -15/2 + b

17/2 = b

Now that we have the slope and the intercept, we can write the equation.

y = 5/6x + 17/2