Question

If a sample of gas of valume 605 mL and temperature of 39 OC, has 0,00803 moles. What is it’s pressure?

Answer 1

Answer: The pressure of the gas is 0.34 atm

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = ?

V = Volume of gas = 605 ml = 0.605 L (1L=1000ml)

n = number of moles = 0.00803

R = gas constant =
`0.0821Latm/Kmol`

T =temperature =
`39^0C=(39+273)K=312K`

`P=(nRT)/(V)`

`P=(0.00803* 0.0821 L atm/K mol* 312K)/(0.605L)=0.34atm`

The pressure of the gas is 0.34 atm