Three consecutive even integers are 20, 22 and 24
Step-by-step explanation
Suppose, the three consecutive even integers are
and

Given that, sum of first and third integers is 22 less than 3 times the second integer. So, the equation will be....

So, the first integer is 20, the second integer is (20+2)= 22 and the third integer is (20+4)= 24