Question

How many moles of oxygen atoms are in 125 g of ba3(po4)2?

Answer 1

Answer: 1.6 moles of oxygen atoms

Explanation:-

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=(125g)/(602g/mol)=0.2moles`

1 mole of
`Ba_3(PO_4)_2` contains = 8 moles of oxygen atoms

0.2 moles of
`Ba_3(PO_4)_2` contain=
`(8)/(1)* 0.2=1.6` moles of oxygen atoms

Thus 1.6 moles of oxygen atoms are present in 125 g of
`Ba_3(PO_4)_2`.

Answer 2

Number of moles = amount in grams / molar mass

= 125 g of Ba3(PO4)2/ 601.9237 g/mol

=0.208 Mole Ba3(PO4)2

1 mole Ba3(PO4)2 contains 8 mole oxygen

Therefore

0.208 Mole Ba3(PO4)2 * 8 mole oxygen / 1 mole Ba3(PO4)2

=1.664 mole oxygen