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The coordinates of the vertices of △RST are R(−3, −1) , S(−1, −1) , and T(−4, −5) .

The coordinates of the vertices of △R′S′T′ are R′(1, −2) , S′(1, 0) , and T′(5, −3) .



What is the sequence of transformations that maps △RST to △R′S′T′?



Drag and drop the answers into the boxes to correctly complete the statement.

A sequence of transformations that maps △RST to △R′S′T′ is a ______ followed by a ______ .

Answer choices:
translation 1 unit up. rotation of 180 degrees about the origin. rotation of 90 degrees counterclockwise about the origin. reflection across the y-axis.

User Penger
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2 Answers

3 votes

Answer:

I think if i had the same question the answers are translation 1 unit up. and rotation of 90 degrees counterclockwise about the origin.

My answer is in the screenshot below for any future people looking for answers :-)

The coordinates of the vertices of △RST are R(−3, −1) , S(−1, −1) , and T(−4, −5) . The-example-1
User Steve Crook
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1 vote

Given coordinates of △RST are R(−3, −1) , S(−1, −1) , and T(−4, −5) .

and coordinates of the vertices of △R′S′T′ are R′(1, −2) , S′(1, 0) , and T′(5, −3) .

Solution : We know the rule for the new coordinates of rotatation 90°counterclockwise about the origin.The rule is (h, k) ---> (-k,h).

Where (h,k) are the coordinates of original image on axes and (-k,h) are the coordinates of rotated image.

In resulting coordinates of the image first swap the x and y coordinates of the original image and then make the sign opposite of each x-coordinate.

On applying rule (h, k) ---> (-k,h), we get

R(−3, −1) --> R′(1, -3).

S(−1, −1) --> S′(1, -1).

T(−4, −5) --> T′(5, −4).

Let us apply another rule, each of the y-coordinate is getting reduced by 1 by adding 1 to the new coordinates.

Adding 1 to y-coordinates, we get

(1, -3) --> (1,-3+1) --> R'(1,-2)

(1, -1) --> (1,-1+1) --> S'(1,0) and

(5, −4) --> (5,-4+1) --> T' (5,-3).

So, the transformations steps would be:

1) Translation 1 unit up

2) Rotation of 90 degrees counterclockwise.



User ComradeJoecool
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