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Solve 4x^2 - 3 = 3x^2 + 13 by using square roots

User Lewsid
by
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2 Answers

6 votes

Answer:

x = - 4, x = 4

Explanation:


4x^2 - 3 = 3x^2 + 13 \\ \\ 4x^2 - 3 - 3x^2 - 13 = 0 \\ \\ 4 {x}^(2) - 3 {x}^(2) - 16 = 0 \\ \\ {x}^(2) - 16 = 0 \\ \\ {x}^(2) - {(4)}^(2) = 0 \\ \\ (x + 4)(x - 4) = 0 \\ \\ x + 4 = 0 \: \: or \: \: x - 4 = 0 \\ \\ x = - 4 \: \: or \: \: x = 4 \\ \\ x = - 4, \: \: 4

User Sngjuk
by
8.7k points
12 votes
X=4, -4 I think! Hope that helps
User M Abdul Sami
by
7.9k points

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