Question

Solve for d. TYPE ONLY THE NUMERIC ANSWER

2d+2=4

Question 11 options:

Answer 1

your answer is 2

Explanation:

2d+2=4

Subtract 2 from both sides

2d=4

then divide both sides by 2 to get the d by itself

d=2

so your answer is 2

Answer 2

`\boxed{\tt \: d = 1}`

Explanation:

`\bf \: Given \: equation :`

`2d + 2 = 4`

We need to find the value of d.

`\bf \: Solution:`

`\sf \implies2d+2=4`

Step 1 :
`\rm Subtract\; 2\: from\; both\; sides :`

`\sf \implies \: 2d + 2 - 2 = 4 - 2`

• Simplify this :

`\sf \implies2d + 0 = 2`

`\sf \implies2d = 2`

Step 2 :
`\rm Divide \; each \: sides \; by \; 2 :`

`\sf \implies \cfrac{2d}{2} = \cfrac{2}{2}`

`\rm \: Cancel \: the \: LHS :`

• Cancel 2 (which is on the numerator) and cancel 2 (which is on the denominator) by 2 :- [Leave d]

`\sf \implies \cfrac{ \cancel2d}{ \cancel2} = \cfrac{2}{2}`

• Results to,

`\sf \implies \cfrac{ {}^(1) \cancel2d}{ {}^(1) \cancel2} = \cfrac{2}{2}`

`\sf \implies 1d = \cfrac{2}{2}`

We know that 1d = d. So,

`\sf \implies \: d = \cfrac{2}{2}`

`\rm \: Now \:Cancel \: the \: RHS :`

• Cancel 2 (which is on the numerator) and cancel 2(which is on the denominator) by 2 :

`\sf \implies{d} = \cfrac{ \cancel2}{ \cancel2}`

• Results to,

`\sf \implies{d} = \cfrac{ \cancel2 {}^(1) }{ \cancel2{}^(1) }`

`\sf \implies{d} = 1`

Hence, the value of d would be 1.

`\rule{225pt}{2pt}`

I hope this helps!

Let me know if you have any questions.