Final answer:
The local venue sold 560 tickets at $10 each and 440 tickets at $15 each. This was determined by setting up a system of linear equations based on the total tickets sold and the total revenue, and then using the elimination method to solve for the number of each type of ticket.
Step-by-step explanation:
To solve the problem of determining how many of each type of ticket were sold by the local venue, we can set up a system of linear equations. We are given two types of tickets: $10 tickets and $15 tickets. The venue sells a total of 1,000 tickets, which gives us our first equation:
Let x be the number of $10 tickets and y be the number of $15 tickets.
Equation 1: x + y = 1,000
The total amount of revenue collected from selling these tickets is $12,200, leading to our second equation:
Equation 2: 10x + 15y = 12,200
To find the values of x and y, we can use either substitution or elimination method. Let's use the elimination method in this case. To eliminate one of the variables, we can multiply Equation 1 by 10 and subtract it from Equation 2:
10(x + y) = 10(1,000)
10x + 10y = 10,000
Now subtract this result from Equation 2:
(10x + 15y) - (10x + 10y) = 12,200 - 10,000
5y = 2,200
Dividing both sides by 5:
y = 440
To find x, we substitute the value of y into Equation 1:
x + 440 = 1,000
x = 1,000 - 440
x = 560
Therefore, the venue sold 560 tickets at $10 and 440 tickets at $15.