Question

An object is launched from a platform. It’s height (in meters), x seconds after the launch, is modeled by h(x)=-5(x+1)(x-9) how many seconds after the launch will the object hit the ground

Answer 1

Answer: The Object Will Hit The Ground In 9 Seconds

Step-by-step explanation: Allow Me To Show You How I Got This Answer. I Hope This Explanation Helps You Out.

1. The object hits the ground when h(x)=0

2. h(x)=0

3. −5(x+1)(x−9)

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x+1=0 or x-9=0

​x=-1 or x=9

4. I found that h(x)=0 for x=-1, or x=9. Since x=-1 doesn't make sense in This context, the only reasonable answer is x=9.

In conclusion, the object will hit the ground after 9 seconds.

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Answer 2

Answer: 9 seconds

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Step-by-step explanation:

The height will be zero when the object hits the ground. So we need to find the x value(s) that make h(x) = 0 true.

h(x) = 0

-5(x+1)(x-9) = 0

x+1=0 or x-9=0 <--- use zero product property

x=-1 or x=9

The value x represents the time in seconds. Having x = -1 seconds makes no sense, so we ignore that value entirely. The only practical solution is x = 9.

After 9 seconds, the object will have a height of 0. This means the object will hit the ground at the 9 second mark.