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a diver dove to a location 6 3/5 meters below sea leavel. He then dove to a second location 8 1/5 meters below sea level. How many meters are there between the two locations?

User Blunders
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4.8k points

2 Answers

2 votes

Answer:

There are -1 ⅗ between each location.

Explanation:

User Avd
by
5.1k points
2 votes

First location the diver dove = 6 3/5 meters below sea leavel.

Second location the diver dove = 8 1/5 meters below sea leavel.

Let us convert those mixed fractions into improper fraction.

6 3/5 =
(6*5+3)/(5)=(30+2)/(5) = 33/5.

8 1/5 =
(8*5+1)/(5)=(40+1)/(5) = 41/5.

Now, we need to find the difference in depths of locations diver dove.

41/5 - 33/5 =
(41-33)/(5)=(8)/(5)

So, we got 8/5.

Now, we need to convert 8/5 into mixed fraction.

Dividing 8 by 5, we get quotient=1 and remainder 3.

So, the mixed fraction would be
1 (3)/(5).

Therefore, we could say
1(3)/(5) meter is the difference in depths of locations diver dove.

User Csaam
by
5.3k points
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