Answer: The correct answer is 'temperature will get doubled that is option D.
Step-by-step explanation:
Suppose the volume of the bubble is V, at temperature T and Pressure exerted by atmosphere P.
When bubble is blown with more air until the volume doubles the initial volume:
The new volume of the bubble = V'=2V
The new Temperature of the air inside the bubble will change to T'.
And the atmospheric Pressure remains same.
According Charles law:
(At constant Pressure)
![(V_1)/(T_2)=(V_2)/(T_2)](https://img.qammunity.org/2019/formulas/chemistry/middle-school/ad3r6va6ckq5l1jq2ln78ck81lk88tbp60.png)
![(V)/(T)=(V')/(T')](https://img.qammunity.org/2019/formulas/chemistry/middle-school/i6vzvxt4xhpx40g3egxf8cc2e86xudwljx.png)
![T'=(2V* T)/(V)=2T](https://img.qammunity.org/2019/formulas/chemistry/middle-school/kreq5h40cftcdosh9ucihzu2om2h92ox5q.png)
So, this means that temperature will get 2 times the initial temperature of the gas.
Hence, the correct answer is 'temperature will get doubled that is option D.