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Point A lies on the circumference of the unit circle and is in the first quadrant. If the x-coordinate of the point is 0.12, its y-coordinate is .

User Venergiac
by
8.8k points

2 Answers

1 vote

we are given

Point A lies on the circumference of the unit circle

so, we can write equation of circle as


x^2 +y^2 =1^2

now, we are given


x =0.12

so, we can plug it in equation and find y


0.12^2 +y^2 =1^2


y^2=0.9856


y=√(0.9856),\:y=-√(0.9856)

Since, point-A lies in first quadrant

so, both x-value and y-value will be positive

so, we get


y=√(0.9856).............Answer

User Larschanders
by
7.9k points
7 votes

Answer

0.99

Step-by-step explanation

Point A forms a right triangle.

Hypotenuse, c = 1 unit

Base length, x = 0.12 units

Then using the Pythagoras theorem,

y² = c² - x²

y² = 1² - 0.12²

= 2 - 0.0144

= 0.9856

y = √0.9856

= 0.992773891

Answer to the nearest hundredths is 0.99.


User KostaZ
by
7.8k points

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