Question

Point A lies on the circumference of the unit circle and is in the first quadrant. If the x-coordinate of the point is 0.12, its y-coordinate is .

Answer 1

we are given

Point A lies on the circumference of the unit circle

so, we can write equation of circle as

`x^2 +y^2 =1^2`

now, we are given

`x =0.12`

so, we can plug it in equation and find y

`0.12^2 +y^2 =1^2`

`y^2=0.9856`

`y=√(0.9856),\:y=-√(0.9856)`

Since, point-A lies in first quadrant

so, both x-value and y-value will be positive

so, we get

`y=√(0.9856)`.............Answer

Answer 2

0.99

Step-by-step explanation

Point A forms a right triangle.

Hypotenuse, c = 1 unit

Base length, x = 0.12 units

Then using the Pythagoras theorem,

y² = c² - x²

y² = 1² - 0.12²

= 2 - 0.0144

= 0.9856

y = √0.9856

= 0.992773891

Answer to the nearest hundredths is 0.99.