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Find the common difference of the arithmetic sequence shown 1/4 3/8 1/2

User Andy Poes
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2 Answers

4 votes

Each fraction can be rewritten with an 8 in the denominator //

1/4 -> 2/8

3/8 = 3/8

1/2 -> 4/8


From left to right, each fraction is increasing by 1/8.

User Henry Rodriguez
by
7.8k points
4 votes

Answer:

Common difference, d
=(1)/(8)

Explanation:

Given: The sequence is arithmetic
(1)/(4),(3)/(8),(1)/(2)


\text{First term, }a_1=(1)/(4)


\text{Second term, }a_2=(3)/(8)


\text{Third term, }a_3=(1)/(2)

To find: Common difference, f

Common difference is equal to difference of second term minus first term.( Difference of any two consecutive term)


\text{Common difference, }d=a_2-a_1=a_3-a_2


d=(3)/(8)-(1)/(4)


d=(3-2)/(8)


d=(1)/(8)

Hence, The common difference of the given arithmetic sequence is
(1)/(8)

User Ocha
by
8.3k points

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