Answer:
Common difference, d
![=(1)/(8)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/a0pyxp85oceicy8ss3ctbedwefoyhr5176.png)
Explanation:
Given: The sequence is arithmetic
![(1)/(4),(3)/(8),(1)/(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/3765s3gyhp81vqpzo5nj39s7r76n2r3tfb.png)
![\text{First term, }a_1=(1)/(4)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/5b6i02vm23v7chuh3713v16mw9xthfbuaq.png)
![\text{Second term, }a_2=(3)/(8)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/9ly9qd0hus9lviagyk08590gyogdqy9q7x.png)
![\text{Third term, }a_3=(1)/(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ay27y429ck5famr0fsv4emymgcxfruzh3e.png)
To find: Common difference, f
Common difference is equal to difference of second term minus first term.( Difference of any two consecutive term)
![\text{Common difference, }d=a_2-a_1=a_3-a_2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/kfxcbz52c40ta3wmbe0o0ueakowhxm1i1n.png)
![d=(3)/(8)-(1)/(4)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/p43hgsizjala590he2ugmeisv595s1sihs.png)
![d=(3-2)/(8)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/91oyz0qaonh2bv7l8gz84g5bb6ze7t6dhq.png)
![d=(1)/(8)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/muhok2q9c4y6ktgqqew19ij88wbjcaurj5.png)
Hence, The common difference of the given arithmetic sequence is
![(1)/(8)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/xo3uyizbh4boa1l1ti30h9zj5qeh413osb.png)