Question

Suppose you have a 2.0 molar solution of sodium hydroxide (naoh), and you need 65 ml of 0.6 molar naoh. how should you make this solution?

Answer 1

The given molarity of sodium hydroxide solution = 2.0 M

The required concentration of sodium hydroxide is 65 mL of 0.6 M NaOH

Converting 65 mL to L:

`65mL*(1L)/(1000mL) =0.065L`

Calculating the moles of NaOH in the final solution:

`0.065L * (0.6 mol)/(L) =0.039mol`

Finding out the volume of 2.0 M solution taken to prepare the final solution:

`0.039 mol * (1L)/(2.0mol)=0.0195L*(1000mL)/(1L) =19.5mL`

Therefore, 19.5 mL of 2.0 M NaOH solution and make it up to 65 mL to prepare 0.6 M NaOH solution.