Question

Turner's treadmill runs with a velocity of -1.3 m/s and speeds up at regular intervals during a half-hour workout. after 25 min, the treadmill has a velocity of -6.5 m/s. what is the average acceleration of the treadmill during this period ?

Answer 1

The average acceleration of the treadmill during this period is 0.00346 m/s²

Step-by-step explanation:

It is given that,

Initial velocity of the treadmill, u = 1.3 m/s

After 25 minutes, the treadmill has a velocity of 6.5 m/s

Final velocity of the treadmill, v = 6.5 m/s

Time taken, t = 25 minutes = 1500 seconds

We need to find the average acceleration of the treadmill during this period. It is given by :

`a=(v-u)/(t)`

`a=(6.5\ m/s-1.3\ m/s)/(1500\ s)`

`a=0.00346\ m/s^2`

So, the average acceleration of the treadmill during this period is 0.00346 m/s². Hence, this is the required solution.

Answer 2

Given : Initial velocity = -1.3 m/s

Final Velocity = -6.5 m/s.

Time = 25 minutes.

To find : Average acceleration.

Solution: We are given units in meter/second (m/s).

So, we need to convert time 25 minutes in seconds.

1 minute = 60 seconds.

25 minutes = 60*25 = 1500 seconds.

Formula for average acceleration is given by,

`(Final \ velocity -Initial \ velocity)/(Final \ time - Initial \ time )`

We are not given intial time, so we can take initial time =0.

Plugging values in the above formula.

`Average \ acceleration = (-6.5 -(-1.3))/(1500-0)`

=
`(-5.2)/(1500)`

= -0.003467

or
`Average \ acceleration = -3.467 * 10^(-3)\ m/s^2.`.