Question

I need help with solving it

Answer 1

parallel lines have the same exact slopes, thefore "q" must also have the same slope as "p", wait a second, what's p's slope anyway? let's see the equation, low and behold, the equation is already in point-slope form, therefore,

`\bf \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}~\hspace{10em}y+2=\stackrel{\stackrel{slope}{\downarrow }}{\cfrac{-9}{7}}(x-3)`

so we're really looking for the equation of a line whose slope is -9/7 and runs through (2, -4).

`\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-4})~\hspace{10em} slope = m\implies \cfrac{-9}{7} \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-4)=-\cfrac{9}{7}(x-2) \implies y+4=-\cfrac{9}{7}x+\cfrac{18}{7} \\\\\\ y=-\cfrac{9}{7}x+\cfrac{18}{7}-4\implies y=-\cfrac{9}{7}x-\cfrac{10}{7}\impliedby \textit{slope-intercept form}`

Answer 2

sorry I can't lol but hope someone else can