12.0k views
1 vote
How do i solve g=(x-c)/x for x? I'm lost on problems like these with division problems and more than one x that I'm solving for.

User Raju Ahmed
by
7.7k points

2 Answers

4 votes

The idea is to bring x to the numerators:

You start by saying
x\\eq 0 (it's a denominator). Then you multiply both sides by x (which is legit, since you are multiplying for something which isn't zero). Then you get
gx = x-c. Add
c-gx to both sides, and you get - reading right to left -
(1-g)x = c and, AFTER stating that
g \\eq 1 (you can't divide by zero!!)
x= \frac {c}{1-g}

User Ajas Aju
by
7.9k points
3 votes

you can group all the x together and then factor out x and then divide.

g = (x-c)/x

multiply both sides by x and u get

gx = x - c

move all x terms together... subtract x from both sides

gx - x = -c

factor out x via reverse distributive property

x(g-1) = -c

divide both sides by g-1

x = -c/(g-1)

if you want to make it look like the other answer (they are both equivalent), if you factor out a negative 1 from the denominator, you get


x=(-c)/(-1(-g+1)) = (-c)/(-1(1-g)) = (c)/(1-g)

User Diego Moreira
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories