Question

A rectangle has a length of x and a width of 5x^3 4-x^2. Find the perimeter of the rectangle when the length is 5 feet.

Answer 1

The perimeter of a rectangle with given dimensions can be found by substituting the value of the length into the width expression and then using the formula 2 * (length + width).

Step-by-step explanation:

Your question seems to relate to the concept of finding the perimeter of a rectangle. The perimeter of a rectangle is determined by doubling the sum of the length and width. If a rectangle has a length of x and a width of
`5x^3 - x^2`, and we know the length is 5 feet, we can find the perimeter by plugging in the value of x into the expression for the width. However, there seems to be an issue with the width's expression; there should be an operator between
`'5x^3' \ and \ '4-x^2'.`Assuming there's a typo, let's consider the width is correctly written as
`5x^3 + (4 - x^2).`

To find the width, replace 'x' with '5':

`Width = 5(5)^3 + (4 - (5)^2) = 5(125) + (4 - 25) = 625 - 21 = 604 feet.`

Then, compute the perimeter:

Perimeter = 2 * (length + width) = 2 * (5 + 604) = 2 * 609 = 1218 feet.

This gives us the perimeter of the rectangle when the length is 5 feet.

Answer 2

1060 feet.

Step-by-step explanation:

We have been given that a rectangle has a length of x and a width of
`5x^3-4x^2`. We are asked to find the perimeter of rectangle when the length is 5 feet.

We know that perimeter of rectangle is two times the sum of length and width of rectangle.

`\text{Perimeter}=2(l+w)`

`\text{Perimeter}=2(x+5x^3-4x^2)`

Upon substituting
`x=5`, we will get:

`\text{Perimeter}=2(5+5(5)^3-4(5)^2)`

`\text{Perimeter}=2(5+5*125-4*25)`

`\text{Perimeter}=2(5+625-100)`

`\text{Perimeter}=2(630-100)`

`\text{Perimeter}=2(530)`

`\text{Perimeter}=1060`

Therefore, the perimeter of the rectangle is 1060 feet.