Question

The position of a particle as a function of time is given by x = (2.0 m/s)t + (-3.0 m/s2)t2. (a) plot x-versus-t for time from t = 0 to t = 1.0 s. (do this on paper. your instructor may ask you to turn in this plot.) this answer has not been graded yet. (b) find the average velocity of the particle from t = 0.45 s to t = 0.55 s. m/s (c) find the average velocity from t = 0.49 s to t = 0.51 s.

Answer 1

Part a)

Equation of position with time is given as

`x = (2.0 m/s)t + (-3.0 m/s2)t^2`

since this equation is a quadratic equation

so it will be a parabolic graph between t = 0 to t = 1

part b)

at t = 0.45 s

`x = 2* 0.45 - 3 * 0.45^2`

`x_1 = 0.2925 m`

at t = 0.55 s

`x = 2* 0.55 - 3*0.55^2`

`x_2 = 0.1925`

now the displacement is given as

`d = x_2 - x_1`

`d = 0.1925 - 0.2925 = -0.1 m`

so the average velocity is given by

`v = (d)/(t)`

part c)

at t = 0.49 s

`x = 2* 0.49 - 3 * 0.49^2`

`x_1 = 0.2597 m`

at t = 0.51 s

`x = 2* 0.51 - 3*0.51^2`

`x_2 = 0.2397 m`

now the displacement is given as

`d = x_2 - x_1`

`d = 0.2397 - 0.2597 = -0.02 m`

so the average velocity is given by

`v = (d)/(t)`