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The value -2 is a lower bound for the zeros of the function shown below f(x)=4x^3-12x^2-x+15

true or false

2 Answers

2 votes

Answer:

The answer is true

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We already know that each and every zero is always between a positive and a negative number.

We get f(-3)=-63, which is a negative number.

As a result, this is the lower bound and the answer is true

User Alexey G
by
7.9k points
4 votes

We are given

The value -2 is a lower bound for the zeros of the function shown below f(x)=4x^3-12x^2-x+15

So, firstly, we will find value of f(x) at x=-2

we will plug x=-2 into f(x)

we get


f(x)=4x^3-12x^2-x+15

we will plug x=-2


f(-2)=4(-2)^3-12(-2)^2-(-2)+15

now, we can simplify it


f(-2)=-32-12\cdot \:4-\left(-2\right)+15


f(-2)=-63

so,


f(-2)=-63 <0

we know that any zeros always lies between positive and negative value

Here , we got f(-3)=-63 ...which is negative value

so, this is lower bound

Hence , this is TRUE

User LightCZ
by
7.9k points

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