Which is a correct factorization of 391? A.(20 - 3)2 B.(20 - 3)(20 + 3) C.(20 - 9)(20 + 9) D.(20 + 3)2

asked Jul 14, 2019 103k views

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Which is a correct factorization of 391?

A.(20 - 3)2
B.(20 - 3)(20 + 3)
C.(20 - 9)(20 + 9)
D.(20 + 3)2

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1 vote

the answer is c
(20x20)+(20x9)-(9x20)-(9x9)
=391

Amomum answered Jul 16, 2019

7.8k points

3 votes

The answer is option B.

Because (20 - 3) (20 + 3)

= (20)^2 - 3^2

=400 - 9

=391.

Fabio Lolli answered Jul 19, 2019