Answer: -2
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Step-by-step explanation:
The equation y = 5x^2-10x+3 is in the form y = ax^2+bx+c
a = 5
b = -10
c = 3
Use the values of 'a' and 'b' to compute the following
h = -b/(2a)
h = -(-10)/(2*5)
h = 1
This is the x coordinate of the vertex point. Use this to find the y coordinate of the vertex.
y = 5x^2-10x+3
y = 5*1^2-10*1+3
y = -2
The vertex is located at (1, -2)
This is the lowest point since a = 5 is a positive value
Positive values of 'a' mean the parabola opens upward, and we have a lowest point at the bottom of the parabola.
So the input x = 1 leads to the smallest output y = -2.
This is the smallest or minimum value of f(x).