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12 ÷ {[(6 × 5) ÷ (4 + 1) ÷ 2] + 1} =


ASAP

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Real easy PEMDAS situation here.

First we handle parentheses and we have a lot of 'em! Starting with the (6 x 5) and (4 + 1):

12 ÷ [(30 ÷ 5 ÷2) + 1]

Now, we handle the division left-to-right inside the parenthesis. 30 ÷ 5 = 6, then 6 ÷ 2 = 3:

12 ÷ (3 + 1)

Last bit of parentheses:

12 ÷ 4

Now divide:

3

EDIT: Changed the word "handled" to "handle." Just a word tense correction.

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