Phosphoric acid have three protons which is ionized in different . Thats why it is called triprotic acid. The protonisation of phosphoric acid in different can be shown as-→. This is the first ionization. The second and third ionizations are shown as-→+ and → + P
=5 is near to first equivalence point where = ( + =(2.15+6.82)=4.6. At this , will be present.
At =10, which is near to second equivalence point= (6.82+12.38)=9.7. At =10, will be present.
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