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50 POINTS PLEASE NO FAKE ANSWERS I REALLY NEED THESE ANSWERED

1. The following reaction shows calcium chloride reacting with silver nitrate.

CaCl2 + 2AgNO3 → 2AgCl + Ca(NO3)2

How many grams of AgCl are produced from 30.0 grams of CaCl2?

(Molar mass of Ca = 40.078 g/mol, Cl = 35.453 g/mol, O = 15.999 g/mol, Ag = 107.868 g/mol, N = 14.007 g/mol)

19.4 grams
38.8 grams
58.2 grams
77.5 grams

2. The table shows the recipe and the available ingredients for making the maximum possible number of sandwiches.


Making Sandwiches
Recipe for One Sandwich Ingredients Available
2 cheese slices, 1 ham slice, 2 bread slices 12 cheese slices, 10 ham slices, 12 bread slices


If the ingredients represent reactants of a chemical reaction, which of the following represents the leftover reactant?
Two ham slices
Four ham slices
Two cheese slices
Four cheese slices

3. Read the given chemical reaction.

C2H6 + O2 → CO2 + H2O

How many moles of H2O are produced during the complete combustion of 1.4 moles of C2H6?

2.8 moles
4.2 moles
5.6 moles
7.0 moles

4. The image represents the reaction between a certain number of molecules of N2 and H2.

[IMAGE INCLUDED]

If the maximum possible amount of NH3 is formed during the reaction, what is the leftover reactant?

One molecule of N2
One molecule of H2
Two molecules of N2
Two molecules of H2

50 POINTS PLEASE NO FAKE ANSWERS I REALLY NEED THESE ANSWERED 1. The following reaction-example-1
User Tektiv
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6.3k points

2 Answers

12 votes

Final answer:

To find the number of grams of AgCl produced from 30.0 grams of CaCl2, we need to use stoichiometry. The correct answer is 77.5 grams.

Step-by-step explanation:

To find the number of grams of AgCl produced from 30.0 grams of CaCl2, we need to use stoichiometry. First, calculate the number of moles of CaCl2 using its molar mass:

Moles of CaCl2 = mass / molar mass = 30.0 g / (40.078 g/mol + 2 * 35.453 g/mol) = 0.371 moles

According to the balanced equation, the molar ratio between CaCl2 and AgCl is 1:2. Therefore, the moles of AgCl produced will be twice the moles of CaCl2:

Moles of AgCl = 2 * 0.371 moles = 0.742 moles

Finally, calculate the mass of AgCl:

Mass of AgCl = moles * molar mass = 0.742 moles * (107.868 g/mol + 35.453 g/mol) = 77.5 grams

User Marknery
by
6.0k points
7 votes
1.B 2.A 3.B 4.D is your answers
User Narnik Gamarnik
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6.6k points