Question

When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

a. 4
b.14
c. 16
d.20
e. 50

Answer 1

1. 3x^2 - 2y
2. 2x^2 - 3y

First expression

• 3(3)^2 - 2(5) = 3(9) - 10
• 27 - 10 = 17

Second expression

• 2(3)^2 - 3(5) = 2(9) - 15
• 18 - 15 = 3

17 - 3 = 14

B. 14